Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (alystar):

How to do inverse functions?

OpenStudy (alystar):

f(x)=sqr(2x-6)

OpenStudy (jackthegreatest):

\[y = \sqrt{2x-6}\]

OpenStudy (jackthegreatest):

is that right?

OpenStudy (alystar):

yes!

OpenStudy (jackthegreatest):

if it is, all you need to do is flip x and y

OpenStudy (jackthegreatest):

\[x = \sqrt{2y-6}\]

OpenStudy (jackthegreatest):

are you able to solve for y?

OpenStudy (alystar):

OH Wow thats a lot easier than I figured. That makes sense though. I was just confused from more complicated problems. Thanks!

OpenStudy (jackthegreatest):

yep np

OpenStudy (jackthegreatest):

tell me the answer when your done

OpenStudy (alystar):

y=(x^2/x)+3

OpenStudy (jackthegreatest):

i got \[y = \frac{ x^2 + 6 }{ 2}\]

OpenStudy (mathmale):

JACK: please go through Alystar's solution step by step to help him/her with any errors.

OpenStudy (jackthegreatest):

mathmale i am

OpenStudy (mathmale):

But let him/her do the actual work!

OpenStudy (jackthegreatest):

i am seeing if he can see what is wrong first

OpenStudy (jackthegreatest):

(or her)

OpenStudy (alystar):

So if the question is to find the inverse of f(x) would the answer be just \[y = \frac{ x^2 + 6 }{ 2}\]

OpenStudy (jackthegreatest):

yes, im trying to figure where you went wrong

OpenStudy (alystar):

or do you not even have to simplify it

OpenStudy (jackthegreatest):

wait a min

OpenStudy (jackthegreatest):

you were right!

OpenStudy (jackthegreatest):

i didnt simplify, ha!

OpenStudy (jackthegreatest):

we have equivalent answers :D:D:D

OpenStudy (alystar):

Haha! okay. So, it doesn't matter which answer I use. Great! Thanks!

OpenStudy (alystar):

@mathmale , we're good here. Thanks

OpenStudy (jackthegreatest):

well depending on your teacher, mine doesnt care whether fraction like that or not, it looks neater some times in one fraction

OpenStudy (mathmale):

Accuracy is everything. Looks come second. ;)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!