Question

@jackthegreatest
3. (-2x^8) x 3y^9 x 2x^4
A. 2x^12y^9
B. -12x^72y^9
C. -12xy^21
D. -12x^12y^9

Answer 1

hmm just a bit harder i guess

Answer 2

\[-2x^8 \times 3y^9 \times 2x^4\]

Answer 3

is that right?

Answer 4

Yeah but (-2x^8) is in perentathse

Answer 5

same thing haha, anyways
just multiply the number
and add the exponents
y^9 stays the same

Answer 6

hopefully not confusing...

Answer 7

haha so wait add the exponents 8 and 4?

Answer 8

yep

Answer 9

So 12

Answer 10

yep

Answer 11

multiply the numbers in front of exponents

Answer 12

all of them includeing the one with the exponent of y^9?

Answer 13

nope multiply that as well

Answer 14

Soooo -2 x 3 x 2?

Answer 15

yes

Answer 16

-12

Answer 17

correct, now just multiply the rest together

Answer 18

12 x -12?

Answer 19

-12x^12xy^9

Answer 20

?

Answer 21

D?

Answer 22

A is suppsosted to be 3 instead of 2 btw

Answer 23

yep d

Answer 24

Awesome, thanks. I have 2 more.

Answer 25

sorry for the long reply

Answer 26

Thats tottaly fine