Yes, rotation and a slide is correct, so describe in detail the rotation and the slide, perhaps using the ordered pair rules, or words, whichever your teacher expects.
I will love to help further, but since it is a test, I must stop somewhere.
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OpenStudy (devonhoward15):
me and weaver were gonna work on it together cause we are in the same class
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OpenStudy (mhchen):
You can use the reflection, and translation properties.
OpenStudy (3mar):
Now we are at the rotation
\[l=\sqrt{x^2+y^2}=\sqrt{1^2+5^2}=\sqrt{26}\]
OpenStudy (devonhoward15):
is that what i put?
OpenStudy (3mar):
No wait
OpenStudy (devonhoward15):
ok
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OpenStudy (devonhoward15):
was that not the final answer?
OpenStudy (3mar):
It is not the final result.
OpenStudy (devonhoward15):
ok
OpenStudy (3mar):
I have a relationship of 90 rotation, but it is not quiet correct when I apply it.
OpenStudy (devonhoward15):
so you dont know part b?
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OpenStudy (devonhoward15):
its fine if you dont... you can just give me the one thats close
OpenStudy (3mar):
I got it
Sorry for late
OpenStudy (devonhoward15):
ok... no rush mate
OpenStudy (3mar):
Not close, it is the correcr and complete role In Sha' Allah
OpenStudy (3mar):
As we have just traslated the triangle 4 units down, now we want to rotate it 90 counter cw
Because the point or the center of rotation is not the origin (0,0) - and that what made me confused - then we will rotate the shape about the center of rotation (-1,-1) let them:
\[(x_o,y_o)=(-1,-1)\]
ok?
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OpenStudy (devonhoward15):
ok
OpenStudy (3mar):
Nice!
OpenStudy (devonhoward15):
so thats the answer?
OpenStudy (3mar):
You are in rush now ;)
OpenStudy (devonhoward15):
no lol... just not sure if that is the answer or not
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OpenStudy (devonhoward15):
or if theres more
OpenStudy (3mar):
The general role states:
OpenStudy (3mar):
as our angle of rotation is 90, then cos(90)=0 and sin(90)=1
then it leads us to:
\[x'=y\]
and
\[y'=-x\]
OpenStudy (devonhoward15):
ok
OpenStudy (3mar):
But this is for rotation about (0,0)
In our case, just a small modification:
\[x'=y-x_o\]
and
\[y'=-x-y_0\]
and apply that at A and B
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OpenStudy (3mar):
I am so sorry if I get you confused or was late.
OpenStudy (devonhoward15):
this has been late for a week lol... trying to get in though so she can grade it... but like i said no rush... as long as we finish and have the answer we are good
OpenStudy (3mar):
Thanks for your patience!
OpenStudy (devonhoward15):
just when you put the final answer say final answer
OpenStudy (3mar):
I have done now!
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OpenStudy (devonhoward15):
was the final answer "y'=-xy
OpenStudy (devonhoward15):
and is that a zero on the end?
OpenStudy (3mar):
\[x'=y-x_o\]and\[y'=-x-y_o\]
' for the new points (after rotation)
OpenStudy (devonhoward15):
is that a zero at the end?
OpenStudy (3mar):
where?
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OpenStudy (devonhoward15):
behind the y
OpenStudy (3mar):
it is subscribe\[y_o\]
this is the point of rotation \[(x_o,y_o)=(-1,-1)\]
OpenStudy (devonhoward15):
how do you make that?
OpenStudy (3mar):
did you try the point C for example?
OpenStudy (devonhoward15):
.c
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OpenStudy (3mar):
I mean A or B.....
OpenStudy (devonhoward15):
im confused lol
OpenStudy (3mar):
ok
no problem
step by step
OpenStudy (devonhoward15):
i have part a and b done... i just need help making the little symbol thing
OpenStudy (devonhoward15):
○
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OpenStudy (3mar):
1 min please
OpenStudy (devonhoward15):
all i need to know is how to make this
OpenStudy (devonhoward15):
how do i make that little circle on microsoft word
OpenStudy (3mar):
do you have Skype id?
OpenStudy (devonhoward15):
no
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OpenStudy (3mar):
any sofware for communication?
OpenStudy (devonhoward15):
i have kik
OpenStudy (3mar):
i don't
OpenStudy (devonhoward15):
thats it
OpenStudy (3mar):
imo?
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OpenStudy (devonhoward15):
no... i have a phone i cant text people
OpenStudy (devonhoward15):
*can
OpenStudy (mathmale):
Please focus strictly on the Math so that you have a chance of getting these problems solved. No more side comments, please.
Devon: please share what YOU yourself have done if you want feedback on it. Sounds as though you are constantly asking for assurance that you're right; that's not going to help you build confidence.
OpenStudy (3mar):
word #??
OpenStudy (devonhoward15):
but is there an alt code to get that little circle?