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oh im only in 6th grade
@jhonyy9
@HolsterEmission
i meant 2 is d lol
3 is a
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@kailey7277 are you positive?
not positive but that's what i think
For (1), having \(110\) heterozygotes out of \(238\) total offspring means that \(2pq=\dfrac{110}{238}\approx 0.46\). Given that \(p+q=1\), you should be able to solve for \(p\) and \(q\), which would correspond to the frequencies for \(\mathrm T\) and \(\mathrm t\).
@steve816 @TheSmartOne
@jackthegreatest @phi please help with some bio questions pleaseeee
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