Question

At which value of x is the slope of the curve y = (1+x^2)^-1 the steepest?

Answer 1

So I found the derivative of this, but how do I find the steepest point?

Answer 2

Lemme try saying it in a strange way,
and see if you can get the hint.

You're trying to `maximize` your slope values.
Hmmm any ideas? :)

Answer 3

Hmm, still not so sure.

Answer 4

@zepdrix

Answer 5

To maximize a function, you take a derivative and do some stuff.
So to maximize slope, which is your derivative function,
you would take a derivative and do some stuff, ya?

Answer 6

Ohh wait something just clicked on my head, does that mean I have to find the second derivative and see when the slope is 0?