At which value of x is the slope of the curve y = (1+x^2)^-1 the steepest?

Question

steve816 · Answer

So I found the derivative of this, but how do I find the steepest point?

zepdrix · Answer

Lemme try saying it in a strange way,
and see if you can get the hint.

You're trying to `maximize` your slope values.
Hmmm any ideas? :)

steve816 · Answer

Hmm, still not so sure.

steve816 · Answer

@zepdrix

zepdrix · Answer

To maximize a function, you take a derivative and do some stuff.
So to maximize slope, which is your derivative function,
you would take a derivative and do some stuff, ya?

steve816 · Answer

Ohh wait something just clicked on my head, does that mean I have to find the second derivative and see when the slope is 0?

zepdrix · Answer

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