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Mathematics 42 Online
OpenStudy (dopeeaf):

Help ? Medal and fan!! In a medical study, the heights of a group of men were measured to the nearest inch. There were 120 men with heights of 60–64 inches, 280 men with heights of 65–69 inches, 312 men with heights of 70–74 inches, and 162 men with heights of 75–79 inches. Which probability distribution table best reflects the data?

OpenStudy (dopeeaf):

OpenStudy (holsteremission):

What's the total of men in the sample? What proportion of this makes up each category? (Each \(P\) value is given by \(\dfrac{\text{number of men in height range}}{\text{total number of men}}\))

OpenStudy (dopeeaf):

to get the total men wouldn't you have to add 120 , 280 , 312, and 162 right ?

OpenStudy (dopeeaf):

@HolsterEmission

OpenStudy (phi):

yes, first add up to get the total number of men. what do you get ?

OpenStudy (phi):

then find the fraction of men in the first group. that means find 120/total (change to a decimal... a calculator is useful). what number do you get ?

OpenStudy (dopeeaf):

i got 1274

OpenStudy (phi):

did you add up 120 , 280 , 312, and 162 ? if we rounded that to 100+300+300+200 that is 900. the answer should be near 900 try again.

OpenStudy (dopeeaf):

okay this time i got 874

OpenStudy (phi):

yes, that looks better now find the fraction in the first group. can you do that ?

OpenStudy (dopeeaf):

uhh how do you do that ..?

OpenStudy (phi):

you find the ratio of number of men in the first group compared to the total number 120/total

OpenStudy (dopeeaf):

ooh so it would be 120/874 ?

OpenStudy (phi):

yes, but use a calculator to make it a decimal (so we can compare it to the answer choices)

OpenStudy (dopeeaf):

0.13 ??

OpenStudy (phi):

I would use more decimals

OpenStudy (dopeeaf):

or wait it would be 0.137 my bad

OpenStudy (phi):

it looks like only 1 choice has that number so that is probably the answer we could check the 2nd group, 280/874 just to be sure.

OpenStudy (dopeeaf):

and by dividing that you would get 0.320 so the answer would have to be C

OpenStudy (phi):

yes.

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