Given the equation of a line y = -1/4x + 10 demonstrate on the whiteboard how to an equation of a line parallel and/or perpendicular to this line that goes through the point (8, -3).

Question

Given the equation of a line y = -1/4x + 10  demonstrate on the whiteboard how to  an equation of a line parallel and/or perpendicular to this line that goes through the point (8, -3).

jiteshmeghwal9 · Answer

If there is a line ax+by+c=0 then a line parallel to it would be ax+by+c'=0 and a line perpendicular to it would be ax-by+c''=0

563blackghost · Answer

Parallel lines have the same slope but different y-intercepts. So we would keep the slope as `-1/4x`. Now we need it to go through the points `(8,-3)` so we would plug it into the slope-intercept form equation with `-1.4x` as its slope to find b....

$\huge{-3=-\frac{1}{4}(8)+b}$

Simplify to find b :)