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Mathematics 11 Online
OpenStudy (jamaljunior):

https://gyazo.com/ea8994cb90223d3256168bb931785e25 Answers: https://gyazo.com/d893483a989c86632ef00f922795b2a7 https://gyazo.com/3d845260862261db7006bf7dab835e04

OpenStudy (jamaljunior):

these are all different links btw ^

OpenStudy (jamaljunior):

@3mar

OpenStudy (3mar):

Well, I am here.

OpenStudy (jamaljunior):

hey :^)

OpenStudy (3mar):

one by one ok?

OpenStudy (jamaljunior):

kk

OpenStudy (jamaljunior):

i hate these graphs

OpenStudy (3mar):

WHy, man!

OpenStudy (jamaljunior):

idk lol

OpenStudy (3mar):

so I know?

OpenStudy (jamaljunior):

false

OpenStudy (3mar):

Where are you stuck?

OpenStudy (jamaljunior):

i havent even started

OpenStudy (3mar):

so let's start

OpenStudy (jamaljunior):

ok

OpenStudy (3mar):

1 min

OpenStudy (3mar):

To deal with such problems, firstly treat the inequality as an equation with = sign. Then represent it on the graph and test the areas on its sides; which one is matches the < or > signs of the original inequality.

OpenStudy (jamaljunior):

um ok

OpenStudy (jamaljunior):

.-.

OpenStudy (3mar):

So what is the equation of the first inequality ?

OpenStudy (jamaljunior):

y = -3x -2

OpenStudy (3mar):

what straight line represent it? the solid or the dotted?

OpenStudy (3mar):

Easy man!

OpenStudy (3mar):

\[\le or \ge solid \rightarrow < or > dotted\]

OpenStudy (3mar):

Jamal?

OpenStudy (jamaljunior):

I'm sorry

OpenStudy (jamaljunior):

the dotted because theres no _ under it

OpenStudy (3mar):

hope it is ok Thank you for the medal!

OpenStudy (3mar):

Are you fine?

OpenStudy (3mar):

Can you proceed?

OpenStudy (jamaljunior):

yes

OpenStudy (jamaljunior):

idk how but im here now

OpenStudy (3mar):

Ok

OpenStudy (3mar):

For the first equation:\[y=-3x-2\] and it is represented by dotted straight line because the sign < in its original inequality

OpenStudy (jamaljunior):

okay

OpenStudy (3mar):

For the second equation: \[y=x-2\] and it is represented by solid straight line because the sign \[\le\] in its original inequality.

OpenStudy (3mar):

Is it fine until here?

OpenStudy (jamaljunior):

yes

OpenStudy (3mar):

Are you busy?

OpenStudy (jamaljunior):

yes

OpenStudy (jamaljunior):

ill try to respond faster

OpenStudy (3mar):

Ok. Never mind.

OpenStudy (jamaljunior):

huh

OpenStudy (jamaljunior):

are you there?

OpenStudy (3mar):

Well, I am here.

OpenStudy (3mar):

2 min please

OpenStudy (jamaljunior):

ok

OpenStudy (jamaljunior):

hey

OpenStudy (3mar):

Sorry! It is an emergency call.

OpenStudy (jamaljunior):

oh are you ok?

OpenStudy (3mar):

not really

OpenStudy (3mar):

sorry

OpenStudy (jamaljunior):

should i have someone else help?

OpenStudy (3mar):

Sorry for being late! It was an emergency call.

OpenStudy (3mar):

This pic would help you to determine which area matches the solution! Thank you for the medal!

OpenStudy (3mar):

So your correct answer will be this.

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