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OpenStudy (iwanttogotostanford):
@sweetburger @FaiqRaees
OpenStudy (iwanttogotostanford):
@jango_IN_DTOWN @tkhunny
OpenStudy (jango_in_dtown):
(ai+bj).(ci+dj)=ac+bd
OpenStudy (iwanttogotostanford):
I think it is 1,9
OpenStudy (jango_in_dtown):
so here 6(-5)+5*4=-30+20 =?
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OpenStudy (iwanttogotostanford):
-10
OpenStudy (jango_in_dtown):
right
OpenStudy (iwanttogotostanford):
oh wow thanks!! Can you help with just 2 more?
OpenStudy (jango_in_dtown):
ok.
OpenStudy (iwanttogotostanford):
my thinking was the last one
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OpenStudy (jango_in_dtown):
a1=-3, a2=2a1=-6, a3=2a2=-12 and so on. now write only the first six terms only
OpenStudy (iwanttogotostanford):
-3, -6, -4, -2, 0, 2
OpenStudy (iwanttogotostanford):
@jango_IN_DTOWN
OpenStudy (iwanttogotostanford):
which one would it be? my tutor is understanding i need the resolution
OpenStudy (jango_in_dtown):
nope... a3=2a2=-12, a4=2a3=-24
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OpenStudy (jango_in_dtown):
a5=2a4=-48
OpenStudy (iwanttogotostanford):
oh so its between A and B....
OpenStudy (jango_in_dtown):
its B
OpenStudy (iwanttogotostanford):
oh ok.... i get it just was stuck in the moment
OpenStudy (iwanttogotostanford):
what about this: Find an explicit rule for the nth term of the sequence.
2, -8, 32, -128, ...
an = 2 ● 4n+1
an = 2 ● (-4)n
an = 2 ● 4n-1
an = 2 ● (-4)n-1
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OpenStudy (iwanttogotostanford):
I appreciate your help kind person!
OpenStudy (jango_in_dtown):
what is a2/a1?
OpenStudy (iwanttogotostanford):
a2
OpenStudy (jango_in_dtown):
a2 means second term a1 is 1st term.
OpenStudy (jango_in_dtown):
write them
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OpenStudy (iwanttogotostanford):
it is B
OpenStudy (iwanttogotostanford):
I wrote them on my online paper
OpenStudy (jango_in_dtown):
its d
OpenStudy (iwanttogotostanford):
oh my online paper told me that but i got confused
OpenStudy (dumbcow):
The focus is always inside the parabola
The focus is on the y-axis, so the parabola is vertical therefore y is function of x
Use following equation
\[y = \frac{1}{4p} x^2\]
where "p" is distance from vertex to focus
Here assume vertex is origin (0,0)
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OpenStudy (iwanttogotostanford):
what would the final solution be?
OpenStudy (iwanttogotostanford):
@imqwerty @jango_IN_DTOWN
OpenStudy (iwanttogotostanford):
hello?
OpenStudy (iwanttogotostanford):
?
OpenStudy (iwanttogotostanford):
would it be D??
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OpenStudy (iwanttogotostanford):
^^^^^^^^^^^^^^^^^
OpenStudy (iwanttogotostanford):
@jango_IN_DTOWN
OpenStudy (iwanttogotostanford):
@jango_IN_DTOWN
OpenStudy (jango_in_dtown):
ok. let me check. wait a bit
OpenStudy (jango_in_dtown):
See the distance of any point on the parabola and the perpendicular distance from the directrix will be same. so
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OpenStudy (jango_in_dtown):
\[\sqrt{(x-0)^2+(y-6)^2}=\sqrt{(y+6)^2}\]
OpenStudy (jango_in_dtown):
so. x^2+y^2-12y+36=y^2+12y+36
so x^2=24y
OpenStudy (jango_in_dtown):
now you tell me the answer
OpenStudy (jango_in_dtown):
y= (1/24) x^2
OpenStudy (iwanttogotostanford):
oh ok thats what i got before. Thanks! I missed the x^2 though
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OpenStudy (iwanttogotostanford):
i think 6/5...
OpenStudy (jango_in_dtown):
\[f(x)=-10/x\]
OpenStudy (iwanttogotostanford):
yes..
OpenStudy (jango_in_dtown):
what is f'(x)?
OpenStudy (iwanttogotostanford):
I am bad at explaining myself mathematically.... I just got 6/5
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