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Mathematics 7 Online
OpenStudy (iwanttogotostanford):

HELP ASA

OpenStudy (iwanttogotostanford):

@sweetburger @FaiqRaees

OpenStudy (iwanttogotostanford):

@jango_IN_DTOWN @tkhunny

OpenStudy (jango_in_dtown):

(ai+bj).(ci+dj)=ac+bd

OpenStudy (iwanttogotostanford):

I think it is 1,9

OpenStudy (jango_in_dtown):

so here 6(-5)+5*4=-30+20 =?

OpenStudy (iwanttogotostanford):

-10

OpenStudy (jango_in_dtown):

right

OpenStudy (iwanttogotostanford):

oh wow thanks!! Can you help with just 2 more?

OpenStudy (jango_in_dtown):

ok.

OpenStudy (iwanttogotostanford):

my thinking was the last one

OpenStudy (jango_in_dtown):

a1=-3, a2=2a1=-6, a3=2a2=-12 and so on. now write only the first six terms only

OpenStudy (iwanttogotostanford):

-3, -6, -4, -2, 0, 2

OpenStudy (iwanttogotostanford):

@jango_IN_DTOWN

OpenStudy (iwanttogotostanford):

which one would it be? my tutor is understanding i need the resolution

OpenStudy (jango_in_dtown):

nope... a3=2a2=-12, a4=2a3=-24

OpenStudy (jango_in_dtown):

a5=2a4=-48

OpenStudy (iwanttogotostanford):

oh so its between A and B....

OpenStudy (jango_in_dtown):

its B

OpenStudy (iwanttogotostanford):

oh ok.... i get it just was stuck in the moment

OpenStudy (iwanttogotostanford):

what about this: Find an explicit rule for the nth term of the sequence. 2, -8, 32, -128, ... an = 2 ● 4n+1 an = 2 ● (-4)n an = 2 ● 4n-1 an = 2 ● (-4)n-1

OpenStudy (iwanttogotostanford):

I appreciate your help kind person!

OpenStudy (jango_in_dtown):

what is a2/a1?

OpenStudy (iwanttogotostanford):

a2

OpenStudy (jango_in_dtown):

a2 means second term a1 is 1st term.

OpenStudy (jango_in_dtown):

write them

OpenStudy (iwanttogotostanford):

it is B

OpenStudy (iwanttogotostanford):

I wrote them on my online paper

OpenStudy (jango_in_dtown):

its d

OpenStudy (iwanttogotostanford):

oh my online paper told me that but i got confused

OpenStudy (dumbcow):

The focus is always inside the parabola The focus is on the y-axis, so the parabola is vertical therefore y is function of x Use following equation \[y = \frac{1}{4p} x^2\] where "p" is distance from vertex to focus Here assume vertex is origin (0,0)

OpenStudy (iwanttogotostanford):

what would the final solution be?

OpenStudy (iwanttogotostanford):

@imqwerty @jango_IN_DTOWN

OpenStudy (iwanttogotostanford):

hello?

OpenStudy (iwanttogotostanford):

?

OpenStudy (iwanttogotostanford):

would it be D??

OpenStudy (iwanttogotostanford):

^^^^^^^^^^^^^^^^^

OpenStudy (iwanttogotostanford):

@jango_IN_DTOWN

OpenStudy (iwanttogotostanford):

@jango_IN_DTOWN

OpenStudy (jango_in_dtown):

ok. let me check. wait a bit

OpenStudy (jango_in_dtown):

See the distance of any point on the parabola and the perpendicular distance from the directrix will be same. so

OpenStudy (jango_in_dtown):

\[\sqrt{(x-0)^2+(y-6)^2}=\sqrt{(y+6)^2}\]

OpenStudy (jango_in_dtown):

so. x^2+y^2-12y+36=y^2+12y+36 so x^2=24y

OpenStudy (jango_in_dtown):

now you tell me the answer

OpenStudy (jango_in_dtown):

y= (1/24) x^2

OpenStudy (iwanttogotostanford):

oh ok thats what i got before. Thanks! I missed the x^2 though

OpenStudy (iwanttogotostanford):

i think 6/5...

OpenStudy (jango_in_dtown):

\[f(x)=-10/x\]

OpenStudy (iwanttogotostanford):

yes..

OpenStudy (jango_in_dtown):

what is f'(x)?

OpenStudy (iwanttogotostanford):

I am bad at explaining myself mathematically.... I just got 6/5

OpenStudy (iwanttogotostanford):

im bad at explaining how i get somewhere

OpenStudy (jango_in_dtown):

what is d/dx(1/x) ???

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