20x^2-26x+8=0

Which of the below are equal to 0? Using the equation above, check all that apply.

x=2/3
x=1/5
x=3/5
x=1/2
x=1/3
x=4/5

Question

20x^2-26x+8=0

Which of the below are equal to 0? Using the equation above, check all that apply.

x=2/3
x=1/5
x=3/5
x=1/2
x=1/3
x=4/5

princeharryyy · Answer

try replacing x =1/2 in the equation

will.h · Answer

you need to find the zeros? 
if so you will have to use 
$$\frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }$$

eliesaab · Answer

Solve the quadratic equation to get x=1/2 or x=4/5

eliesaab · Answer

Use the quadratic formula

will.h · Answer

@eliesaab share your steps don't give direct answers

brightemmerald · Answer

We have to turn the equation into a binomial, then try to turn the binimials = to 0.

will.h · Answer

have you learn about the famous quadratic formula? 
the one i posted?

eliesaab · Answer

Or factor it
$$
20 x^2-26 x+8=2 (2 x-1) (5 x-4)
$$

brightemmerald · Answer

attachment

will.h · Answer

okay so group factoring is pretty good way too

20x^2-26x+8=0

1st of all what is the GCF?

brightemmerald · Answer

4 is the GCF

will.h · Answer

great 
simplify 
what would be the new shape of the expression?

brightemmerald · Answer

wait... 26  doesnt have a GCF of 6

brightemmerald · Answer

err 4

will.h · Answer

good note
so what would be the GCF?

eliesaab · Answer

attachment

will.h · Answer

that would help indeed @eliesaab you deserve a medal