Question

A student has some $1 bills and $5 bills in his wallet. He has a total of 15 bills that are worth $47. How many of each type of bill does he have?

Answer 1

7 of them are 1s and 8 of them are 5s.

Answer 2

47-7 = 40
40/5= 8.
so you have 7 ones and 8 fives

Answer 3

I need better work...

Answer 4

well I just estimated, you should say you did that. I dont know what the actual solution would be

Answer 5

I'm not writing that down.. Sorry.

Answer 6

so its 8 five dollar bills and 9 one dollar bills??

Answer 7

No, it's 7 $1 bills and 8 $5 bills.
But, I don't know how to show my work.

Answer 8

wait no There are 7 $1 bills and 8 $5 bills.

Answer 9

oh

Answer 10

did you learn in school to estimate or did you learn an actual solution?

Answer 11

The actual solution.

Answer 12

so n = 15 - m = 15 - 8 = 7

Answer 13

oh ok, sorry I dont know then. what grade is this?

Answer 14

11th Grade - Algebra II

Answer 15

oh ok i am only in algebra 1

Answer 16

x + y = 15
x + 5y = 47

use substitution method
x = -y + 15
x + 5y = 47

now substitue x in the 2nd equation

(-y + 15) + 5y = 47
4y + 15 = 47
4y = 32
y = 8

now let's find x
x + y = 15
we know that y = 8
x + 8 = 15
x = 7

Now we know we have 7 1s and 15 5s

make sense?

Answer 17

top one

Answer 18

lol Thx

Answer 19

u mean 8 5s, since y = 8

Answer 20

oh yes 8 5s and and 7 1s

Answer 21

Thank you, @Will.H !

Answer 22

sure

Answer 23

let me know if you have other questions
i have recently completed alg 2

Answer 24

Will do!