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what's h(-3) given h(x) = -/2 - x/?
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PLug in -3 where the x is. And then solve.
\[h(x) = -|2 - x|\]
Substitution. That's how the notation works. If f(x) = 3 + x, then f(2) = 3 + 2 If h(x) = x - 9/x, then h(4) = 4 - 9/4
so 1? still kinda confused
Did you substitute '-3' everywhere is says 'x' in the definition?
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-5?
Are you guessing? Please show your work.
no im not guessing. -/2 - (-3)/ 2- (-3) = 5 -5
Excellent. Go with confidence.
thank you
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