f(x)=x(4-x)^6 what are all of the critical points?
Have you considered the 1st Derivative?
Yeah that's where I'm having trouble. I used the product rule to find the derivative but idk how to find x lol
Demonstrate? What did the derivative look like?
(4-x)^6+x[-6(4-x)^5]
That's good. Now factor it and make it prettier. It will also be more convenient.
Factor or foil?
"FOIL" doesn't exist. Let's leave that in Algebra 1. Please FACTOR. Find common factors in each term and apply the Distributive Property.
okay so distribute
6 times..
No, factor. a*b + a*c = a*(b+c)
ahh so (4-x)^5(4-x-6x) ???
That's the spirit. Now what?
set them both equal to 0, but for the (4-x-6x), is that [(4-x)(-6x)] or (4-7x)?
You have to do better than that. 4 - x - 6x = ??? You tell me. No guessing.
well it's equal to 0. But when i factored out the (4-x) in the beginning, there was a -6x(4-x) left. So it should really be -24x+6x^2=0 right?
Please simplify properly, using addition, 4 - x - 6x = ??
why addition?
Do you see anything else? Combine like terms using whatever operation is there.
well i was saying before that it should be multiplied right?? not added together
OH WAIT NVM
I was looking at the wrong part of it. THANK YOU SO MUCH
Where is the multiplication in 4 - x - 6x? You once turned it into multiplication when you wrote "[(4-x)(-6x)]". However, that was only magic. You cannot turn addition (or subtraction) into multiplication.
So the anwers are x=4, 4/7
Yea i was factoring it out weird in my head :P
Not quite. Those are the x-values of the critical points. You have not quite answerd the "where are" part of the question.
oh well I would plug those back into the original f(x) to find the y. But this is multiple choice and it just says x= lol
Fair enough. Good work.
Thank you for the help and your time! :)
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