Question

When is the slope of this = to 0?

Answer 1

\[\frac{ x^2+2x-8 }{ x+6 }\]

Answer 2

\[f'(x)=\frac{ 2x+2(x+6)-(x^2+2x-8) }{ (x+6)^2 }\]

Answer 3

\[2x+2x+12-x^2-2x+8=0\]

Answer 4

so then i got -(x^2-2x-20)=0 but how can i factor this?

Answer 5

ok you did f' right

Answer 6

sweet

Answer 7

where did i mess up?

Answer 8

+ 14x, not + 2x

Answer 9

you multiplied wrong

Answer 10

2x+14x+12−x2−2x+8=0

Answer 11

OMG I'm stupid af. I should've put that into parenthesis. Thank you! xD

Answer 12

np