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There are four naturally occurring isotopes of the element chromium. The relative abundance of each is 50Cr 4.345% 49.946044 amu 52Cr 83.789% 51.940508 amu 53Cr 9.501% 52.940649 amu 54Cr 2.365% 53.93880 amu Find the average atomic mass of chromium.
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\[\sum \frac{(\text{Atomic mass of each element * percentage abundance})}{100}\]
Average atomic mass =\[\frac{50*4.345+52*83.789+53*9.501+54*2.365}{100}\]
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