http://prntscr.com/crihaf I forgot how to do this.
FIRST: what is the slope of the solid line (it is simple - take the two endpoints from the graph and use delta y/delta x)
If you take the points I suggest tehn the answer is immediately evident (it is simple - take the two endpoints from the graph and use delta y/delta x)
There is insufficient information. Your visual assumption of the points the line passes through hardly constitutes evidence of the actual points on the line.
Actually, based on the graph, you can see the intersection points. So you can find the slope, the y-intercept, and basically the equation of both lines,
To get the line equation, you need a point on the line and the direction of the line. Or, 2 points on the line. I would use points where the line goes through a cross in the gridlines and assume it is exactly over the gridline cross. Some points on the line are (x,y) (-2 , 5) (0 , 4) (2, 3) (4,2) You can use any 2 to get an equation.
@Gokuporter: Please become involved in this discussion. What do you understand, and what do you not understand?
@mhchen Actually, you are only assuming you see it as it is. |dw:1476055467731:dw| It's a right triangle because it is DEFINED to be so. Visual appearance is NOT significant.
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