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Why is the determinant of x'x(x transpose x) 0 ?
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multiplied by zero?
No no the determinant of x'x is 0 ...my question is how ?
\[ x=\left( \begin{array}{cc} 1 & 2 \\ 3 & 5 \\ \end{array} \right) \]
\[ x'=\left( \begin{array}{cc} 1 & 3 \\ 2 & 5 \\ \end{array} \right) \]
\[ x x'=\left( \begin{array}{cc} 5 & 13 \\ 13 & 34 \\ \end{array} \right)\]
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So Det(x x')=1, so it is not zero in general
Also Det[ x'x]=1
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