Question

a=11+4b−4c
solve for c.

Answer 1

Alright so flip the equation.
\(\ 4b−4c+11=a\)

Answer 2

Alright so add \(\ -11\) to both sides.
\[\ 4b−4c+11+−11=a+−11\]
\[\ 4b−4c=a−11\]
So than add \(\ -4b\) to each side
\[\ 4b−4c+−4b=a−11+−4b\]
\[\ −4c=a−4b−11\]

Answer 3

Your last step woule be dividing both sides by \(\ -4.\)
\[c=\frac{ -1 }{ 4 }a=\frac{ a−4b−11 }{ -4 }\]

Answer 4

So your final answer should be \[c=\frac{ -1 }{ 4 }a+b+\frac{ 11 }{ 4 }\]