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What number must you add to complete the square? x^2 + 12x = -5 A. 144 B. 36 C. 6 D. 12
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did you see what I wrote earlier?
i accidentally deleted it
ax^2 + bx + c (b/2)^2 = the number you add to complete the square
take 12/2 and then square it
or well the only square that will get you 12x is (x+6)(x+6)
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When the coefficient of the x^2 term is 1, add the square of half of the coefficient of x.
That was a lot of similar information at once.
B, 36.
\[x^2+12x=-5\] we need this form to be in that form: \[x^2+12x+(\frac{ 12 }{ 2 })^2-(\frac{ 12 }{ 2 })^2=-5\] then complete the square \[[x^2+12x+36]-36=-5\] \[(x+6)^2-36+5=0\] \[(x+6)^2-31=0\]
are those the correct options?
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Are you positive? jdaub18
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