Question

Two cyclists start at the same point and travel in opposite directions. One cyclist travels 6 mi/h
slower than the other. If the two cyclists are
114mi apart after 3 hours, what is the rate of each cyclist?

Will medal and fan

Answer 1

Make the faster guy have a rate r. The slower is then r-6.

Distance = rate * time, and time is 3 hours:

3r + 3(r-6) = 114

Answer 2

distance = rate*time
time = 3 hrs
rate for cyclist 1 = r , cyclist 2 = r-6

solve for r