Question

Can someone help me with using Distributive Property to simplify expressions? I know a little on how to do it I just need some help. Thanks.

Answer 1

http://www.coolmath.com/prealgebra/06-properties/05-properties-distributive-01

Answer 2

\[a(b+c+d...)=ab+ac+ad...\]

Answer 3

Wait I have a problem can I tell you it? Its 5 + 6 (m+1) I think I know how to do it.

Answer 4

Do I first make it look like this:
5+6m(1)?

Answer 5

no its 9m+9*1

Answer 6

Then do I multiply 6 and 1? And then have 5+7m and then add them and get 12m?

Answer 7

Ohh okay thank you

Answer 8

I still dont understand how you go t 9 though

Answer 9

\[5+6(m+1)\]Distributive property\[5+(6\times m+6\times1)\]

Answer 10

Okay so I am a little confused the equation switches too 5+(6xm+6+1)?

Answer 11

If you have variables A, B, and C in equation \(A(B+C)\) you would do this, basically\[A\times B+A\times C\]

Answer 12

Or A(B) + A(C), remember to do multiplication first :)

Answer 13

Wow that's confusing sorry xD So after it will look like 5(6m+6)?

Answer 14

And would I multiply 5 by 6 and get 30m. After would I add 30m by 6 and get 36m?

Answer 15

@kittiwitti1

Answer 16

@Twistrose can you help me out?

Answer 17

Hey, can you pick up where we left off?

Answer 18

ok so i go t9 by adding like terms at the beginnning, then distibuting. that

Answer 19

Adding the like terms means 5 and 6 right?

Answer 20

you're suppose to do parenthesis first, then like terms 5+6m+6 (Pemdas)

Answer 21

But its distributive property you carry the like terms to to perenteses

Answer 22

Yeah, you have to do the 6(m+1) part first before anything. Parentheses come before addition.q

Answer 23

Hi kittiwitt1 sorry I just needed some help haha

Answer 24

the distributive property counts on what it's near to if the problem was something like this, it would of made more sense to do it like you say (m+1)(6+5)

Answer 25

5+6(m+1) = 5 + 6m + 6(1) = 5 + 6m + 6 = ?

Answer 26

but it's very basic distributive property problem so you're fine 5+6(m+1)= 5+6m+6

Answer 27

yea you don't touch the 6m so you just add like terms

Answer 28

11+6m last answer

Answer 29

Try:
2(4+7)
Distribute:

Answer 30

@brainzonly is very smart, ask him for help xD
I have to finish my Chem homework x_x

Answer 31

too many people on this question LOL

Answer 32

^

Answer 33

Ugh Chemistry that's hard. Omg this is alot @-@ okay so 5 + (m+6) turns into 5+6m+6 and then I solve that? Ikr but I feel special :DD

Answer 34

@Kevin @kittiwitti1 There are certain people that like to exaggerate my talents. :|

Answer 35

LOOL

Answer 36

Thanks for the medal :D

Answer 37

lol it's simple algebra you should understand the concept

Answer 38

5 + (m+6) could actually be solved this way:
5 + 1(m+6) invisible number :D
5+ 1m +6
1m + 11

Answer 39

woah stop brain stop stop

Answer 40

? This is easy!!!!!

Answer 41

brah's 5+6(m+1) where does that come from

Answer 42

Brainzzzz slow down,,, lol

Answer 43

where does that unknown equation come from chill my mans

Answer 44

I dont understand because first I got 5+6m+6 its really 5 + 1 (m+6)?

Answer 45

that's the way mellamokatie you're on the right path now add the like terms (the ones with no letters)

Answer 46

WHAT!!! NO!!
There is an INViSIBLE NUMBER 1 in front of the (m + 6)
5 + 1(m+6) because 1 times m is just m and 1 times 6 is just 6 so it doesn't distub anything and then 5 + 1m + 6 is 1m + 11 and then that is m + 11

Answer 47

LOOL Afro quit telling me the wrong stuff!!

Answer 48

He's saying 5 + (m+6) has an "invisible number" because any number/value is also a product of itself times 1\(a=a\times1\)

Answer 49

LMAO this is too funny

Answer 50

omg dude 5+6(m+1) bro COME ONN, it's not wrong you are correct bro @ katie

Answer 51

I mean\[a=a\times1\] and Afro is correct

Answer 52

COME ONNNNNNNNN MAN this IS 9TH GRADE STUFF COME ONNNNNN come onnnnnnn