Question

i need help

Answer 1

http://prnt.sc/cuueve

Answer 2

@Astrophysics @eliesaab @F_Jayyy @Lime @SerenityJustice74 @Devonhoward15

Answer 3

i need help wit life tew !

Answer 4

The first step is to convert \(\Large 39^{\circ} \ 45^{\prime}\) into decimal form. Were you able to do this?

Answer 5

how can we covert degree into decimal?

Answer 6

Are you familiar with the idea of `arc-minutes`?

Answer 7

no I am not

Answer 8

maybe i forget

Answer 9

so the idea that `60 arc-minutes = 1 degree` hasn't been discussed by your teacher?

Answer 10

nope

Answer 11

so it turns out that we can break up a degree into 60 equal parts

each part is 1 arc-minute

as you can imagine, 1 arc-minute is a very small measure that's hard to draw out accurately

Answer 12

we have 39 full degrees plus 45 arc-minutes


60 arc-minutes = 1 degree
1 arc-minute = 1/60 degree
45 arc-minutes = 45/60 degrees
45 arc-minutes = 3/4 degrees


So we have 39 full degrees plus 3/4 of a degree

39+3/4 = 39+0.75 = 39.75 degrees

Answer 13

let me know if something doesn't make sense

Answer 14

oh ok so it be 39.75 in decimal

Answer 15

??

Answer 16

yes 39.75 would go in the first box. Do you see how?

Answer 17

yep!

Answer 18

based on that drawing I posted, are you able to find x?

hint: you'll use a trig function

Answer 19

tan39.75=x/115
x=95.64

Answer 20

good

Answer 21

95.64 is the approx height of the building and flagpole combined

Answer 22

y = height of building (ignoring flagpole)
y = ???

Answer 23

tan31=y/115
y=69.09

Answer 24

I got 69.09897

If you round that to 2 decimal places, then it would become 69.10

Answer 25

yes

Answer 26

height of flagpole only = (height of building and flag) - (height of building only)

height of flagpole only = x - y

height of flagpole only = 95.64449 - 69.09897

height of flagpole only = 26.54552 ft approximately

Answer 27

oh ok what is
F + L?

Answer 28

F+L = flag height + library height