Question

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Answer 1

@hoot_hoot

Answer 2

@mathmale

Answer 3

I'm not really sure... Find two factors of 18 and 40. As much as possible, they must have same bases. For 18, I picked 3 and 6. For 40, I chose 5 and 8.

6 = 2*3
8 = 2*4
4 = 2*2

18 = 3*2*3 = \[3^{2} \times 2\]
40 = 5*2*2*2 = \[5 \times 2^{3}\]

You all raise that to 9...
\[(3^{2})^{ 9 } \times 2^{ 9 }\] = \[3^{ 18 } \times 2^{ 9 }\]
\[5^{ 9 } \times (2^{3})^{ 9 }\] = \[5^{ 9 } \times 2^{ 27 }\]

If you combine them, it will be:
\[3^{ 18 } \times 2^{ 36 } \times 5^{ 9 }\]

I'm not really sure if it's correct...