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Physics 19 Online
OpenStudy (word2):

cHECK MY ANSWER!!!!!!!!!!!!

OpenStudy (word2):

The slope of a velocity versus time graph is the object's acceleration displacement >position velocity

OpenStudy (word2):

@tigerlover

OpenStudy (osprey):

ACCELERATION. The slope is the opp over the adjacent of a given tangent to the curve. The opp is the change of velocity, which is a good start. The adj is the change in time, which is even better. Doing the arithmetic that makes the tangent of the angle of the tangent (yes, I know it's there twice) the acceleration. If the acc is "linear" - ie not curved - then it's the slope of the "linear line", so to speak. Just reread the post, to convince myself I'm still making sense ... bon chance, bon voyage http://perendis.webs.com

OpenStudy (word2):

i don't get what your saying

OpenStudy (word2):

@agent0smith

OpenStudy (word2):

@Atsie

jabez177 (jabez177):

I know this but forgot... :/ @sweetburger

OpenStudy (s4sensitiveandshy):

*velocity versus time graph * slope= rise/run according to that graph velocity = rise run= time velocity unit is m/s and s for time \[\frac{velocity }{Time } = \frac{\frac{m}{s}}{s} = \frac{m}{s} * \frac{1}{s} = \frac{m}{s^2}\]which is the unit of acceleration.

OpenStudy (irishboy123):

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OpenStudy (word2):

thank you

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