Solve the system by substitution. y = x^2 - 2x + 1 y = 2x + 1
Alright so we will substitute the value of the 2nd equation in the 1st equation and then we will be able to solve for x 2x + 1 = x^2 -2x + 1 Solve for x you can use famous quadratic formula but 1st set the entire terms on one side
What do you mean set the entire terms on one side? @Will.H
2x + 1 = x^2 -2x +1 Set the left side equal to 0 How? By getting rid of all terms Subtract 1 from both sides and 2x from both sides to get 0 = x^2 -4x Make sense?
Yes @Will.H
Alright. Use famous quadratic formula and find the x values There will be 2 solutions
Find them and tag me to see if you're correct
Umm. Would it be (2,5) and (1,3)? Or am I wrong? @Will.H
You're wrong.
I'll explain
X^2 -4x = 0 We can use factoring method GCF is x so X(x -4) = 0 So either x = 0 Or x-4 = 0 which equal x =4 Make sense?
It does @Will.H
Terrific. Now we will find the y values shall we?
Y = 2x +1 We found x = 0 Or x= 4 So let's find y when x = 0 first Y = 0 + 1 which equal y = 1 Now when x = 4 Y = 2(4) + 1 which equals y = 9 Make sense? That's all
So our solutions are (0, 1) and (4,9) You can ask if something is confusing you. I can explain
Oh it makes sense! Thank you! :) @Will.H
You welcome :)
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