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Algebra
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F = Gm^2/r^2 G = ?
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G is the universal gravitational constant
I don't understand the question, are you asking to approximate G, or solve for G?
solve for g
We can use algebra to solve for G.
yes
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Can you show me what you got so far?
F*r/m
$$ \rm F = \frac{Gm^2}{r^2} \\ ~ \\ Fr^2 = Gm^2 \\ $$ Can you solve for G now?
Fr/m
am I doing something wrong?
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how are you getting Fr/m
\[ \rm F = \frac{Gm^2}{r^2} \\ ~ \\ Fr^2 = Gm^2 \\ ~ \\ \frac{Fr^2}{m^2} = G \] The last step is to divide both sides by \( \rm m^2 \).
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