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Algebra 16 Online
OpenStudy (cthyptrk):

F = Gm^2/r^2 G = ?

OpenStudy (perl):

G is the universal gravitational constant

OpenStudy (perl):

I don't understand the question, are you asking to approximate G, or solve for G?

OpenStudy (cthyptrk):

solve for g

OpenStudy (perl):

We can use algebra to solve for G.

OpenStudy (cthyptrk):

yes

OpenStudy (perl):

Can you show me what you got so far?

OpenStudy (cthyptrk):

F*r/m

OpenStudy (perl):

$$ \rm F = \frac{Gm^2}{r^2} \\ ~ \\ Fr^2 = Gm^2 \\ $$ Can you solve for G now?

OpenStudy (cthyptrk):

Fr/m

OpenStudy (cthyptrk):

am I doing something wrong?

OpenStudy (perl):

how are you getting Fr/m

OpenStudy (perl):

\[ \rm F = \frac{Gm^2}{r^2} \\ ~ \\ Fr^2 = Gm^2 \\ ~ \\ \frac{Fr^2}{m^2} = G \] The last step is to divide both sides by \( \rm m^2 \).

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