Recall that the height of an object t seconds after it begins moving when gravity is the only force acting on the object is given by h(t)=−16t2+v0t+h0, where h(t) is given in feet, v0 is the initial velocity of the object in ft/sec, and h0 is the initial height of the object in feet. If a ball is thrown directly upward from the top of a building with an initial velocity of 44 feet per second, and an initial height of 70 feet. What is the maximum height attained by the ball?

Question

Recall that the height of an object t seconds after it begins moving when gravity is the only force acting on the object is given by h(t)=−16t2+v0t+h0,  where h(t) is given in feet, v0 is the initial velocity of the object in ft/sec, and h0 is the initial height of the object in feet. If a ball is thrown directly upward from the top of a building with an initial velocity of 44 feet per second, and an initial height of 70 feet. What is the maximum height attained by the ball?

steve816 · Answer

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agent0smith · Answer

First plug in the given values.

Then find the vertex of the quadratic equation.

likeabossssssss · Answer

nice latex