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Mathematics 11 Online
OpenStudy (shaima):

will fan and medal

OpenStudy (shaima):

1. The following formula relates the quantities temperature in Celsius (C) and temperature in kelvins (K). C = K − 273.15 (a) Write two other related equations. (b) If the temperature is 23 in degrees Celsius, what is the temperature in kelvins? Show your work. (c) Which is greater, 300 kelvins or 25 degrees Celsius? Show your work.

OpenStudy (dustin_whitelock):

Use the formula dudette

OpenStudy (shaima):

i did this but i forgot my answer ;-;

OpenStudy (dustin_whitelock):

You want to verify with mine?

OpenStudy (shaima):

sure?

OpenStudy (dustin_whitelock):

b) 296.15 degree Celsius c) 300K A)I don't know what this question is asking of me.

OpenStudy (shaima):

its asking u to write a number problem that are related equations

OpenStudy (afro):

can you use other temperature formulas?

OpenStudy (dustin_whitelock):

Like this: K=273.15+C?

OpenStudy (afro):

to get kelvins it's always - 273^ i think she posted the formula wrong

OpenStudy (shaima):

nope thats what my teacher put

OpenStudy (afro):

^ you're correct but just include the C(T)=K(T)-273.16

OpenStudy (dustin_whitelock):

Or you can use a C anf F relation formula

OpenStudy (afro):

no she has to find the kelvin first, i was asking that in relation to question A

OpenStudy (afro):

oh dustin you was right bro it's 23+273.15 that's celsius

OpenStudy (shaima):

OpenStudy (dustin_whitelock):

a is asking for two related equations. since it is a temperature relation, I don't think degree C & degreeF and degree F and K relation equations are wrong. In fact, I think they are the only answers.

OpenStudy (afro):

what i'm saying is she probably has to use, Fahrenheit conversion method as well as celsius as related questions, and for C it's 300-273.15 = 26.85 to find what is greater and for 25 it's 25+273.15= 298.15 which is 298.15-273.15 converted back to celsius is 25

OpenStudy (shaima):

im only in 7th.

OpenStudy (afro):

300- 273.15K is 26.85 celsius and even better you're ahead, remember 273.15k is 0 degress celsius

OpenStudy (afro):

for the 2nd part first you have to convert it twice, first from Celsius to Kelvin which is 25 + 273.15 = 298.15 kelvin, then you have to convert it back from kelvin into Celsius which iss 298.15 - 273.15 = 25

OpenStudy (afro):

same for B just add 23 + 273.15 and you're good

OpenStudy (dustin_whitelock):

But what i said for (a), is that correct @Afro ?

OpenStudy (afro):

with the F to kelvin that's something totally more complicated yea, she can just use celsius

OpenStudy (afro):

@Dustin_Whitelock she could just write for the celsius K=C+ 273.15

OpenStudy (afro):

if she has to use Fahrenheit she's gonna have to do K=(F x 459.67) x 5/9

OpenStudy (dustin_whitelock):

(A) doesn't mean any thing to me, the question is confusing...

OpenStudy (afro):

that's like kinda complicated for a 7th grader if she has to do that's more than i imagine, it's basically saying write 2 equations that are equivalent to this one

OpenStudy (dustin_whitelock):

Yeah, true. So I figured out the other c-f and f-k equations as the answers.

OpenStudy (shaima):

i dont understand

OpenStudy (afro):

-_- lemme draw it

OpenStudy (afro):

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