GEOMETRIC SEQUENCES
The original value of a car is $18,000, and it depreciates (loses value) by 15% each year. What is the value of the car after three years?
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OpenStudy (eliesaab):
After one year it loses .15 *18000
So how much is it worth after one year
OpenStudy (elise_a18):
12000? I have no idea
OpenStudy (eliesaab):
18000 - .15 18000=18000 -2700
OpenStudy (elise_a18):
15300
OpenStudy (eliesaab):
18000-2700=15300
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OpenStudy (eliesaab):
Yes
OpenStudy (elise_a18):
that doesn't help too much for figuring out 3 years
OpenStudy (eliesaab):
Do another year but strat with 15300
OpenStudy (elise_a18):
strat?
OpenStudy (eliesaab):
15300 - .15 * 15300
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OpenStudy (eliesaab):
How much is that?
OpenStudy (elise_a18):
is there no formula to use where I can plug in numbers?
OpenStudy (eliesaab):
Yes, I will get you to the formula when you follow my steps
OpenStudy (elise_a18):
isn't that just making the process longer? You could give me the formula to use and I would know what to do from there :)
OpenStudy (eliesaab):
\[18000*(1-.15)^3\]
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OpenStudy (elise_a18):
17939.25
OpenStudy (eliesaab):
No
OpenStudy (elise_a18):
what did i do incorrect? ono
OpenStudy (eliesaab):
\[
18000 *(0.85)^3=11054.2
\]
OpenStudy (elise_a18):
ahh i see what i did... but why is the exponent on the outside?
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OpenStudy (eliesaab):
The exponent is only for .85
OpenStudy (eliesaab):
18000 is not raised to the power 3
OpenStudy (elise_a18):
ahhh I HATE MAKING STUPID LITTLE MISTAKES
OpenStudy (elise_a18):
srry about caps... X)
OpenStudy (eliesaab):
In general if the original price is P and the depreciation is r %, then the value after in years is
\[
P*(1-r)^n
\]
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