need helpp
It's NOT a function if there's 2 OR MORE y-values for any x-value. Basically, if there's a repeat of a number in "domain" then it's NOT a function. Otherwise it would be a function.
The same x cannot match up with two different y values for that x. In relation A, the 5 elements of the domain all match up with w BUT no single X is matched up with two different values for that x. Conclusion: Relation A is a function.
@burberry22 On relation 2, do you see a single x that is matched up with two different y values for that x?
The x values are the domain. The y values are the range.
I can help you with this but I need for you to participate. Look at relation 2 and see what you think the answer is.
i thikn its a function
sooo? relation 2 is a function
@directrix
>> relation 2 is a function Yes
relation 3 is not a function ithink?
Relation 3 has and x of 5 going to both t and w. You are correct. Relation 3 is not a function.
What is your thinking on relation 4? @burberry22
relation 4 is not a function
You are looking, I think, at the range and seeing where it connects in the domain. That is not what we need to do. Look at the x values and see if the same x goes to two different ys for that x.
oh isee what your saying so ralation 4 is a function
and also can you help me with 2 more questions?
x and w are two different domain values going to 7 in the range. That is okay. Because the exact same x is not going to two different values for that x.
Relation 4 is a function.
> and also can you help me with 2 more questions? I will try to help.
relation 1 is not a function?
>> relation 1 is not a function? Correct.
What about relation 2?
relation 2 would be a relation
>>relation 2 would be a relation But is it a function or not?
Paper goes to x in the range. Paper also goes to t in the range. Therefore, relation 2 is not a function. @burberry22
relation 3
is a relation?
I think you meant to post "is a function."
Is relation 4 a function?
nope
@directix
@directrix
Is relation 4 a function? Yes, it is a function. The same x is not paired with the same y value for that x. @burberry22
Post the next new problem in a new thread, please. @burberry22
Join our real-time social learning platform and learn together with your friends!