could someone help me with this one any help is appreciated thank let f (x)=x^2 + 6 and g (x) =x+8/x find (g o f) (-7) a) 384 /7 b) -57/7 c) 295 /49 d) 63/55 its not C i got that one wrong
(g o f) (-7) means first figure out f(-7) f (x)=x^2 + 6 f(-7) = (-7)^2 + 6 what do you get if you simplify that ?
do you know how to figure out -7* -7 + 6 ?
sorry it's been a long time since i have done calculus i'm getting back into pre calculus that is where they are starting me so i'm trying to refresh my mind
the arithmetic follows rules PEDMAS order of operations are done in the order: parens exponents (powers) division/multiply add/subtract in this problem (-7)^2 + 6 you do the the -7*-7 first then you add 6
once you get a number, you "use" that number in place of x in g(x) = (x+8)/x
ok thank you this helps me i don't know why i was road blocking myself big thank you
welcome to os
thank you very much
np
Join our real-time social learning platform and learn together with your friends!