Help please with this
with ?
What are the zeros? The solutions I mean.
Are they X = -1 And x = -3?
I'm sorry about the blurry picture, but the two sets of points are (-2,-1) and (-1,1)
They are I found so So the zeros are X = -1 and x = -3 That means (x +1) (x + 3) Distribute X^2 + 3x + x + 3 Simplify X^2 + 4x + 3 Proof: Find the vertex -B/2a = -4/2 = -2 Substitute x= -2 to find the value of y (-2)^2 + 4(-2) + 3 = -1 So the vertex is (-2,-1) Which confirms that out solution was correct Hope that helps
Well the question is asking what the equation is?
We found it Y = x^2 + 4x + 3
And I proved that the equation is correct by deriving the vertex
Questions,?
Nope, but if I have the same type of problem with the points (3,-3) and (0,-2) and the parabola is opening to the left
If the sketch indicates the zeros you can fins any equation. If not idk another way
Yes it's the same exact problem just with different points
Post it in a new thread and tag me.
Okay
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