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Mathematics 12 Online
zarkam21 (zarkam21):

Help please with this

jhonyy9 (jhonyy9):

with ?

zarkam21 (zarkam21):

OpenStudy (will.h):

What are the zeros? The solutions I mean.

OpenStudy (will.h):

Are they X = -1 And x = -3?

zarkam21 (zarkam21):

I'm sorry about the blurry picture, but the two sets of points are (-2,-1) and (-1,1)

OpenStudy (will.h):

They are I found so So the zeros are X = -1 and x = -3 That means (x +1) (x + 3) Distribute X^2 + 3x + x + 3 Simplify X^2 + 4x + 3 Proof: Find the vertex -B/2a = -4/2 = -2 Substitute x= -2 to find the value of y (-2)^2 + 4(-2) + 3 = -1 So the vertex is (-2,-1) Which confirms that out solution was correct Hope that helps

zarkam21 (zarkam21):

Well the question is asking what the equation is?

OpenStudy (will.h):

We found it Y = x^2 + 4x + 3

OpenStudy (will.h):

And I proved that the equation is correct by deriving the vertex

OpenStudy (will.h):

Questions,?

zarkam21 (zarkam21):

Nope, but if I have the same type of problem with the points (3,-3) and (0,-2) and the parabola is opening to the left

OpenStudy (will.h):

If the sketch indicates the zeros you can fins any equation. If not idk another way

zarkam21 (zarkam21):

Yes it's the same exact problem just with different points

OpenStudy (will.h):

Post it in a new thread and tag me.

zarkam21 (zarkam21):

Okay

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