solve for x:3/4(3x-1/2)-2/3<1/3
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Hrmm I'm not sure but that's what i got \[ x<\frac{ 11 }{ 18 } \]
Regarding your 3/4(3x-1/2)-2/3<1/3 : I'd strongly suggest that you enclose that "3/4" inside parentheses.: (3/4)(3x-1/2)-2/3<1/3
Same for the remainder of your expression: (3/4)(3x-1/2)-2/3<1/3 would be (3/4)(3x-1/2)-(2/3)<(1/3)
I see three different denominators here: 4, 2 and 3. What's the LCD (lowest common denominator)? Multiply the entire inequality (3/4)(3x-1/2)-(2/3)<(1/3) by the LCD, to remove fractions. (Don't touch the 1/2 yet). Your result?
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