A sphere of radius .1m and mass 8pi is attached to a lower end of a string wire of length 5m and diameter 10^-3 the wire is suspended from 5.22m high cieling of room and when the sphere is made to rotate as circular path as simple pendulum it just graze the surface find velocity of sphere at lowest pt given youngs modulus=2×10^11
Class 11
This q reminds me of the FOUCAULT PENDULUM, an example of which is in the science museum in London, UK. http://perendis.webs.com
@prajwal draw it
At lowest point of oscillation, tension in string wire will be \(T = mg + \dfrac{m \color{red}{v}^2 }{r}\) and you have: \({ Y = \dfrac {\sigma }{\varepsilon }}={\dfrac {T/A_{0}}{\Delta L/L_{0}}}={\dfrac {TL_{0}}{A_{0}\Delta L}}\) You're looking for 0.02m of extension but if you drew that we could see it clearly, especially as it would clarify where/how the sphere is attached to the string. draw it mate :-))
@IrishBoy123 nous parlons avec nous, if you'll pardon my french ... pity because the FP is a very interesting device. Bravo Monsieur F ! Seems a common them among the posts ... ?
Join our real-time social learning platform and learn together with your friends!