What is the vertex form of the equation?

y = -x^2 + 12x - 4

Question

What is the vertex form of the equation?

y = -x^2 + 12x - 4

directrix · Answer

The vertex form of a quadratic is of the format:

y = a*(x-h)^2 + k where (h,k) is the vertex of the parabola. "a" is a constant which we have to figure out to solve this problem.

valirium · Answer

So I have to graph something for this problem?

valirium · Answer

Sorry, I'm not good at these kinds of problems.

directrix · Answer

I think we're going to have to complete the square technique on the given equation to get the vertex form.

directrix · Answer

y = -x^2 + 12x - 4

y = - ( x^2 - 12x + __?__)  - 4   + __?__

directrix · Answer

@Valirium 

What is one-half of negative 12 ?

valirium · Answer

6?

valirium · Answer

ummm -4 and 3?

valirium · Answer

Idk I'm confused

directrix · Answer

Okay, we're on the way.

What is one-half of negative 12 ?  That is negative 6.

directrix · Answer

Any questions?

valirium · Answer

I got it. Thank you for helping! :)

directrix · Answer

You are welcome.