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What is the vertex form of the equation? y = -x^2 + 12x - 4
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The vertex form of a quadratic is of the format: y = a*(x-h)^2 + k where (h,k) is the vertex of the parabola. "a" is a constant which we have to figure out to solve this problem.
So I have to graph something for this problem?
Sorry, I'm not good at these kinds of problems.
I think we're going to have to complete the square technique on the given equation to get the vertex form.
y = -x^2 + 12x - 4 y = - ( x^2 - 12x + __?__) - 4 + __?__
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@Valirium What is one-half of negative 12 ?
6?
ummm -4 and 3?
Idk I'm confused
Okay, we're on the way. What is one-half of negative 12 ? That is negative 6.
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Any questions?
I got it. Thank you for helping! :)
You are welcome.
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