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Algebra 18 Online
OpenStudy (foxie):

WILL FAN AND MEDAL I'm really not sure that I am working my problem correctly. PLEASE help!! Picture of work attached in comments!!

OpenStudy (shadowlegendx):

Attachment?

OpenStudy (foxie):

OpenStudy (shadowlegendx):

You don't distribute the 9 to 6 and 3

OpenStudy (foxie):

Took me a minute to get it up, OS lags for me sometimes. I am 98% sure I distributed the 9 properly so that was what I had was correct so far..

OpenStudy (foxie):

....Why is it not distributed?

OpenStudy (shadowlegendx):

It's \[9 + (6x + 3) \neq 9(6x + 3)\]

OpenStudy (foxie):

MY book says to distribute.. you're solving for x.. I'm not quite understanding your explanation..

OpenStudy (foxie):

Whoops, didn't mean to put my in all caps

OpenStudy (shadowlegendx):

I'm saying that you are distributing, when it is 9+ (6x + 3). You can't do that, 9 is not being multiplied by the parentheses, it is adding by it.

OpenStudy (foxie):

Ohh, okay.. so then how does one work to solve this?

OpenStudy (foxie):

Because if you don't distribute then I am at an utter loss ;-;

OpenStudy (shadowlegendx):

\[-[6x -(4x + 8)] = 9 + (6x + 3)\]

OpenStudy (shadowlegendx):

Looks good so far?

OpenStudy (foxie):

Yes that is the equation.

OpenStudy (shadowlegendx):

What do you think we should do first?

OpenStudy (foxie):

I really have no clue, you can't combine unlike terms so I would have said distribute but since you can't.. uhmm... I really don't know; I could say subtract 3 from 8 but I know that's not it; I would just be guessing.

OpenStudy (shadowlegendx):

You can distribute. We follow PEMDAS Parentheses(Includes Brackets) Exponents Multiplication Division Addition Subtraction We do brackets first, following PEMDAS.

OpenStudy (shadowlegendx):

We do this by distributing the -1 across the left side of the equals sign

OpenStudy (shadowlegendx):

\[-6x + (-4x - 8) = 9 + (6x + 3)\]

OpenStudy (foxie):

You just said we can't distribute. And you can't combine unlike terms so we can't do anything inside the brackets and parenthesis; I do kn ow how pemdas works I'm not a complete idiot but if we can't distribute the 9 and 6 into the brackets then you're stuck with that as the answer and I have to solve for x... I'm assuming the -1 came from outside the brackets and is just "known" that it is there?

OpenStudy (shadowlegendx):

\[\rightarrow -[6x -(4x + 8)] = 9 + (6x + 3)\] _1

OpenStudy (shadowlegendx):

-1

OpenStudy (foxie):

Okay...so if we distribute that to the left we still can't go any further??

OpenStudy (foxie):

...hello?

OpenStudy (shadowlegendx):

\[-6x -4x -8 = 9 + 6x + 3\]

OpenStudy (shadowlegendx):

Like terms \[-10x - 8 = 12 + 6x\]

OpenStudy (foxie):

...Why are the parenthesis just gone??

OpenStudy (shadowlegendx):

Because you can't do anything inside them, or anything to them

OpenStudy (shadowlegendx):

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