Question

Find f^-1 for the function f(x)=^3sqrt x-2 +8.
A)f^-1(x)=(x-8)^3+2
B)f^-1(x)=(x+8)^3+2
C)f^-1(x)=^3sqrt x-8 +2
D)f^-1(x)=(x-8)^3-2

Answer 1

could this be \[f(x)=\sqrt[3]{x-2}+8\]?

Answer 2

yes satellite73

Answer 3

First, your presentation needs work, as satellite73 is hinting by asking for clarification.

Answer 4

i would set \[y=\sqrt[3]{x-2}+8\] then switch \(x\) and \(y\) because that is what the inverse does, and solve \[x=\sqrt[3]{y-2}+8\] for \(y\) in three steps

Answer 5

clear how to do that? if not, try solving \[\sqrt[3]{y-2}+8=5\]
the steps will be the same