Find f^-1 for the function f(x)=^3sqrt x-2 +8.
A)f^-1(x)=(x-8)^3+2
B)f^-1(x)=(x+8)^3+2
C)f^-1(x)=^3sqrt x-8 +2
D)f^-1(x)=(x-8)^3-2

Question

Find f^-1 for the function f(x)=^3sqrt x-2 +8.
A)f^-1(x)=(x-8)^3+2
B)f^-1(x)=(x+8)^3+2
C)f^-1(x)=^3sqrt x-8 +2
D)f^-1(x)=(x-8)^3-2

satellite73 · Answer

could this be $$f(x)=\sqrt[3]{x-2}+8$$?

billyjean · Answer

yes satellite73

mathmale · Answer

First, your presentation needs work, as satellite73 is hinting by asking for clarification.

satellite73 · Answer

i would set $$y=\sqrt[3]{x-2}+8$$ then switch $x$ and $y$ because that is what the inverse does, and solve $$x=\sqrt[3]{y-2}+8$$ for $y$ in three steps

satellite73 · Answer

clear how to do that? if not, try solving $$\sqrt[3]{y-2}+8=5$$  
the steps will be the same