What is the slope of the line passing through the points (0, -5) and (4, 2)?
@shansha1
Also what is the slope 3x+4y=12
slope = rise/run =\[\frac{ y2-y1 }{ x2-x1 }\]
So.... what does that mean?
so here we have (0, -5) and (4, 2 ) (0,-5) =(x1,y1) (4,2)=(x2,y2) put these values in the eq you will get the answer
try to do if there is still any problem let me know :)
Do I have to graph it? I really suck at graphing!!!
no it is not required in the question just solve it
I have no idea what to do
(0,-5) =(x1,y1) (4,2)=(x2,y2) put these values in the following equation : \[\frac{ y2-y1 }{ x2-x1 }\]
So I have to figure out what y2 and so on equals?
you have y2 just put the values for example (1,2) (3,4) here (x1,y1) are (1,2) and (x2,y2) are (3,4) formula is \[\frac{ y2-y1 }{ x2-x1}\] putting the values \[\frac{ 4-2 }{ 3-1 }\] 2/2=1
so you would substitute and then simplify?
yup :)
:) Thanks so much! and 0 would = y1 and -5 would = x1 4 = x2 and 2 =y2?
x1= 0 y1=-5 x2=4 y2=2
my pleasure :)
@smilie2015 is a lifesaver!!!
thnx
:) Have a nice day!
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