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Mathematics 28 Online
OpenStudy (campayne):

What is the cost of renting each item? (Hint: Solve the system of equations you selected in the previous problem, for x, y, and z.) equation is 4Shoes + 5Harnesses +1Bags = 23 6Shoes + 6Harnesses + 0Bags = 30 3Shoes + 7Harnesses + 5Bags = 28

OpenStudy (campayne):

OpenStudy (518nad):

okay look at the 2nd equation that can be simplified

OpenStudy (campayne):

how so?

OpenStudy (518nad):

6Shoes + 6Harnesses + 0Bags = 30 6S + 6H = 30 divide both sides by 6

OpenStudy (campayne):

so 2?

OpenStudy (campayne):

SO IS IT TWO OR NOT?

OpenStudy (mhchen):

no, not yet. he meant that shoes + harnesses = 5

OpenStudy (mhchen):

So we have: 4 shoes + 5 harnesses + 1 bag = 23 1 shoe + 1 harness = 5 3 shoes + 7 harnesses + 5 bags = 28 We can do substitution method: 1 shoe + 1 harness = 5 (1 shoe) = (5 - 1 harnesses) <-- got it? Then using our first equation: 4 shoes + 5 harnesses + 1 bag = 23 4(5 - 1harnesses) + 1 bag = 23 20 - 4 harnesses + 1 bag = 23 -4 harnesses + 1 bag = 3 <-- We got a new equation with only 2 variables. Now do you think you can do the same thing with the third equation, and get another 2 variable equation? I assume that you know how to solve system of equations with only 2 equations and 2 variables right?

OpenStudy (campayne):

not entirely

OpenStudy (mhchen):

This is an extension of this problem: "Find x and y if: ax + by = c dx + ey = f" I'm sure you learned that in class right? There's no way you would've have this problem if you haven't learned system of equations...

OpenStudy (campayne):

true that very true now that i look at it it makes sense

OpenStudy (mhchen):

okay, soo um...back to our original question. I'm gonna make shoes = s, harnesses = h, and b = bag: First equation: 4s + 5h + 1b = 23 Second equation: 1s + 1h = 5 Third equation: 3s + 7h + 5b = 28 In the previous post, we used first and second equation to get: -4h + 1b = 3 Now I want you to try to do the same thing with the second and third equation. Yeah? Think you can do it? Cmon! :) (if you can't, just say so and I'll show you)

OpenStudy (campayne):

okay i tried but it makes zero sense

OpenStudy (mhchen):

Okay so with the second and third equation: (I'll do the exact same thing) We already got: -4h + 1b = 3 Now in order to be able to do system of equation for -4h + 1b = 3, we need another equation with 'h' and 'b' in it: Second and Third Equations: 1s + 1h = 5 3s + 7h + 5b = 28 1s + 1h = 5 (1s) = (5 - 1h) 3(s) + 7h + 5b = 28 3(5 - 1h) + 7h + 5b = 28 15 - 3h + 7h + 5b = 28 4h + 5b = 13 So now we have: 4h + 5b = 13 -4h + b = 3 You can solve this thing right?

OpenStudy (mathmale):

I vote with mhchen: Use the letters s, h, b to represent the rental cost of each the shoes, the harness and the bags.

OpenStudy (mathmale):

What next? Know what to do? You have a system of 3 equations in 3 variables (s, h, b) and must solve for s, h and b.

OpenStudy (campayne):

i see. it still looks like too much i need it broken down individually

OpenStudy (mathmale):

Make a choice: eliminate x first, or eliminate y first, or eliminate z first. Up to you!

OpenStudy (campayne):

x ill get that one

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