Problem Page A line passes through the point , −4−2 and has a slope of −3 . Write an equation in point-slope form for this line.
y-y1 = m*(x-x1) where m is the slope and x1, y1 is the coordinate on the line.
Plug in the values to get the answer
oh ok
Do you know how does one derive to that form of equation? It's called the point slope form.
The derivation of that form comes from the basic definition of slope.
Point-slope form is written like this: (y - y1) = m(x - x1) In point-slope form, y1 is the y value of the known point on the line, m is the slope and x1 is the x value of the known point. In your problem, (x1,y1) = (−4−2) m= −3 Fill that into the form for the line: (y - y1) = m(x - x1)
i have a huge headache can you give m the answer bro?
3x + y + 14 = 0
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