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Algebra
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What is the quadratic function that is created with roots -3 and 1 and a vertex at (-1, -8)?
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quadratic function with known roots: \[f(x)=a(x-p)(x -q)\] where p and q are the roots. So your function is \[f(x)=a(x+3)(x-1)\] Plug in the vertex and solve for \(a\)
ANOTHER WAY TO DO THIS. quadratic function with known vertex: \[f(x)=a(x-h)^2+k\] where (h, k) is the vertex So your function is\[f(x)=a(x+1)^2-8\] Plug in one of the roots and solve for \(a\) You'll get the same function with either method.
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