Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (calculusxy):

Question is in the attachment

OpenStudy (calculusxy):

OpenStudy (calculusxy):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

I think what they're asking is "do any of these objects cross paths?" Maybe they also want to know if any of the objects collide

OpenStudy (mathmate):

Hint: distribute/simplify each expression and then compare.

OpenStudy (calculusxy):

I remember in class we were doing something like figuring out the vectors by comparing one point from each line

jimthompson5910 (jim_thompson5910):

I'm still trying to think of how your teacher wants this done. Do you have class notes at all?

OpenStudy (calculusxy):

Yes like we said, for example, that object a starts at (2,5) and b starts at (4,-2) and c starts at (0,12). The vector from a to b [2,-7] from b to c it would be [-4, 14] and from a to c it would be [-2, 7

OpenStudy (calculusxy):

*[-2,7]

jimthompson5910 (jim_thompson5910):

Maybe he wants you to graph this out? Or make a table?

OpenStudy (calculusxy):

perhaps

jimthompson5910 (jim_thompson5910):

the instructions of "comparing" the objects seems a bit vague to me

OpenStudy (calculusxy):

Alright it's okay. I have a question about a question i asked previously in a separate post

OpenStudy (calculusxy):

Actually nevermind

OpenStudy (calculusxy):

I think i understand :)

OpenStudy (calculusxy):

Thanks so much for helping!

jimthompson5910 (jim_thompson5910):

sure thing

OpenStudy (mathmate):

@calculusxy If you had distributed (expanded) each expression, you will see them as: f(t)=4+5*t,1-3*t g(t)=-6+5t,3-3t, h(t)=9+5*t,-2-3*t Have you noticed that the coefficients of t are all the same? What does that mean? Better still, evaluate f(1), g(3),h(0). What do you get, what does that mean?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!