Question

This question title is clickbait.

Answer 1

Conner and Jana are multiplying (3568)(39610).


Conner's Work
(3^56^8)(3^96^1^0) = 3^5 + ^96^8 + ^1^0 = 3^1^46^1^8
Jana's Work
(3^5^68)(3^96^1^0) = 3^5⋅^96^8⋅^1^0 = 3^4^56^8^0

Is either of them correct? Explain your reasoning.

(I put ^ before every number that's small

Answer 2

Click bait has succeed.

Answer 3

XD wow thee title though

Answer 4

Succeeded*

Answer 5

Yis.

Answer 6

xD

Answer 7

got me so hard

Answer 8

The click bait below seems too be working more

Answer 9

Nvm xD

Answer 10

I wouldn't say Connor is correct, because when you have two numbers, (most likely in parenthesis.) and they have no operation shown, it usually results in multiplication.


Example:


(5)6 = 30.

Answer 11

What about the other one? @MissSmartiez

Answer 12

Also, nice cat picture

Answer 13

:P

Answer 14

By using what I have given you, yes.


x, no operation but numbers close together, and * means multiplication.

Answer 15

Oh, wait. I am reading more into the problem.

Answer 16

Why did you do '^'? Does it resemble an exponent?

Answer 17

Yeah

Answer 18

Ok, then I must ask you.


Is it:
(3568)(39610).

or some numbers consisting in this problem are exponents/obtain exponential forms?

Answer 19

\[((3)^{56})^{8}\]????????????????? or am i misunderstanding how you are using ^

Answer 20

I'll re-type it.

Answer 21

^

Precisely. It troubles me and I feel that we are lacking some important information. It happens. When we copy and paste, the exponents don't normally go through.

Answer 22

I'll re-type it.

Answer 23

Of course. I accidently pressed away... Ugh....