Question

Solve.

5 + d > 5 – d

A.
d > 10

B.
d > 0

C.
d < –5

D.
d > –10

Answer 1

Same as from your last problem you start from simplifying \(d+5>−d+5\)
and add \(d\) to each sides

\[\ d+5+d>−d+5+d\]
\[\ 2d+5>5\]

Answer 2

So -3d > 5?

Answer 3

\( -3d>5\) for what?

Answer 4

idk...

Answer 5

No when you d
\(\ d+5+\color{red}{d}>−d+5+\color{red}{d} \)

Answer 6

after subtracting it from both sides you should get \( 2d+5>5\)

Answer 7

Uh huh...

Answer 8

so d + 3 > 5 is the next step?

Answer 9

After that you subtract 5
\(\ 2d+\color{red}{5}−5>5−\color{red}{5}\)
which would give you \( 2d>0\)

Answer 10

from there try to divide 2 on each side
[\frac{ 2d }{ 2 }\]=\frac{ 0 }{ 2 }\]

Answer 11

So your final answer would be \(d>0\)