I need a rational function that has at least one asymptote and possibly a removable discontinuity. I just can't manage to think of one

Question

3mar · Answer

What do you mean by "possibly a removable discontinuity."??

brokenstanzas · Answer

Meaning there doesn't have to be a removable discontinuity in the equation but there can be @3mar

3mar · Answer

3mar · Answer

@brokenstanzas

danjs · Answer

for a removable discontinuity, you can use a piecewise function.

3mar · Answer

Thank you for the medal!

agent0smith · Answer

$$\large f(x) = \frac{ (x-3)(x+4) }{ (x-3) (x-8) }$$has a hole at x=3 which is really a removable discontinuity, and a vert asymptote at x=8.

brokenstanzas · Answer

@agent0smith Thank you!!

leenathan · Answer

please close this question so that the system wont have to work as hard

3mar · Answer

@agent0smith 
Really I thank you!!

This is what she was looking for!