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How did I get this one wrong? a=1/3 and r=1/3 r < 1 Doesn't that mean Convergent?
@Nnesha
r isn't 1/3
Oh yea huh....
What would r be then? :/
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denominator: 3, 6, 9,12,15 a_1+3= a_2 a_2+3=a_3 so each term is increasing by 3 3n now to find the value of r substitute 1 for n 3(1)+ r = 1/3(first term)
bruh
bruh thats the same thing 1/3 * sum (1/x) for x from 1 to inf
lol
like bruh
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ok brother
u know 1/3 is divergent
i mean i know 1/x is
i mean u know
no i don't know ;-; so you're saying that \[\lim_{x \rightarrow \infty} \frac{1}{x}\] is divergent ??
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I am totally confused.. lol
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