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Mathematics 21 Online
OpenStudy (itz_sid):

HELP PELASE

OpenStudy (itz_sid):

How did I get this one wrong? a=1/3 and r=1/3 r < 1 Doesn't that mean Convergent?

OpenStudy (itz_sid):

@Nnesha

Nnesha (nnesha):

r isn't 1/3

OpenStudy (itz_sid):

Oh yea huh....

OpenStudy (itz_sid):

What would r be then? :/

Nnesha (nnesha):

denominator: 3, 6, 9,12,15 a_1+3= a_2 a_2+3=a_3 so each term is increasing by 3 3n now to find the value of r substitute 1 for n 3(1)+ r = 1/3(first term)

OpenStudy (518nad):

bruh

OpenStudy (518nad):

bruh thats the same thing 1/3 * sum (1/x) for x from 1 to inf

Nnesha (nnesha):

lol

OpenStudy (518nad):

like bruh

Nnesha (nnesha):

ok brother

OpenStudy (518nad):

u know 1/3 is divergent

OpenStudy (518nad):

i mean i know 1/x is

OpenStudy (518nad):

i mean u know

Nnesha (nnesha):

no i don't know ;-; so you're saying that \[\lim_{x \rightarrow \infty} \frac{1}{x}\] is divergent ??

OpenStudy (itz_sid):

I am totally confused.. lol

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