ANTIDERIVATIVES Consider the function f(x)=10cosx−8sinx. Let F(x) be the antiderivative of f(x) with F(0)=8.
The part that is throwing me off, is the F(0)=8
That is an initial condition so that you can solve what the + C is equal to.
So do I find the antiderivatve of 10cos-8sinx, and have that equal to 8?
Kind of, I think you need to plug 0 into the antiderivative with + C and set that equal to 8. I think what you said was correct, I was just over thinking it.
i\[10\sin(0)+8\cos(0)+C=8\]
ah ok I got it, C would then be equal to zero
YES very good.
I hope I remember this correctly.
That sounds familiar to what I learned in class today. I think I was mistaking it as a separate function because I was getting a completely different answer. Thanks!
yw
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