Question

sin2x equals?

Answer 1

Hey Leslie!
\(\large\rm \color{salmon}{\text{Welcome to OpenStudy! :)}}\)

Is your expression \(\rm \sin(2x)\) or is the 2 supposed to be an exponent? \(\rm \sin^2x\) ?

Answer 2

And what are you trying to do?
Rewrite it in another form?

Apply Sine Double Angle Identity?

Need more information.

Answer 3

↑ What he said.

If you have \(\sin^{2}\theta\), then you can also put it in the form \(1-\cos^{2}\theta\) by rule of Pythagorean identity.
If you have \(\sin{2\theta}\), then you can apply the Double Angle formula, which is \(\sin{2\theta}=2\sin{\theta}\cos{\theta}\)

Answer 4

The Pythagorean Identity is as follows:\[\cos^{2}\theta+\sin^{2}\theta=1\]

Answer 5

By the way, theta and \(x\) are interchangeable variables. It doesn't matter what you use.\[\theta\leftrightarrow x\]

Answer 6

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Answer 7

That... was seriously not necessary...