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Solve for x and y. 3x−y+19i=1+(2x+3y)i
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I'm confused on where to start.
Imaginary number
ohh ok, than that makes stuff complicated.
Exactly
The real parts, and the imaginary parts, on each side need to be equal. The real part on the left is 3x-y. It needs to be equal to the real part on the right, which is 1. The imaginary part on the left is 19. It needs to be equal to the imaginary part on the right, which is 2x+3y.
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Okay I understand that
3x-y=1 (2x+3y)i=19i
Now what? Do I plug in y?
Y=3x-1
19-2x=3y
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19-2x=3(3x-1)
?
Yes, solve for x. Then you can use it to find y.
X=2
Y=5
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Thank you so much
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