Question

The coordinates of the vertices of a polygon are (0,3), (2,3) (2,0), (1,-4) and (-2,-1). 
What is the perimeter of the polygon to the nearest tenth of a unit? 

Answer 1

@3mar

Answer 2

Well, I am here.

Answer 3

Find the distance between each point.

\(\huge\bf{d=\sqrt{(2-0)^{2}+(3-3)^{2}}}\)
\(\huge\bf{d=\sqrt{(2-2)^{2}+(0-3)^{2}}}\)
\(\huge\bf{d=\sqrt{(1-2)^{2}+(-4-0)^{2}}}\)
\(\huge\bf{d=\sqrt{(-2-0)^{2}+(-1-3)^{2}}}\)

Answer 4

Add each of these up to find the perimeter.

Answer 5

Two ways:
1: plot all these points and you can see the shape (square, rec, ....)

2: calculate the distance between every two points (sides' lengths) then sum their lengths

which one are you familiar with?

Answer 6

both

Answer 7

@hmayberry
563blackghost did the job very well.
So you can follow what she wrote and add them up to get the perimeter!

Answer 8

Okay thank you so much

Answer 9

Thank you @3mar :)

Answer 10

You are welcome, sister!

Answer 11

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